aider moi svp a) 3x – 5 = 6 – 2x b) (4x – 3)(7x + 5) = 0 c) x² - 36 = 0
Mathématiques
salma13130
Question
aider moi svp
a) 3x – 5 = 6 – 2x
b) (4x – 3)(7x + 5) = 0
c) x² - 36 = 0
a) 3x – 5 = 6 – 2x
b) (4x – 3)(7x + 5) = 0
c) x² - 36 = 0
1 Réponse
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1. Réponse maudmarine
Bonjour,
a) 3x – 5 = 6 – 2x
3x + 2x = 6 + 5
5x = 11
x = 11/5
b) (4x – 3)(7x + 5) = 0
4x - 3 = 0 ou 7x + 5 = 0
4x = 3 7x = - 5
x = 3/4 x = - 5/7
c) x² - 36 = 0
(x - 6) (x + 6) = 0
x - 6 = 0 ou x + 6 = 0
x = 6 x = - 6.