Svpp aidez moii Exercice 3 : Développer puis réduire les expressions suivantes A = (4x – 8) – (3x – 7) + (-2x + 3) B = (6x² – 5x + 7) – (4x² – 5x – 5) C = – (3x

Bonjour,

A=(4x-8)-(3x-7)+(-2x+3)

 =4x-8-3x+7-2x+3

A= -x+2

B=(6x²-5x+7)-(4x²-5x-5)

 =6x²-5x+7-4x²+5x+5

B=2x²+12

C=-(3x²-5x+2)+(2x²-2x+8)-(3-2x+2x²)

  =-3x²+5x-2+2x²-2x+8-3+2x-2x²

C=-3x²+5x+3

Hello :)

A = (4x - 8) - (3x - 7) + (-2x + 3)

A = 4x - 8 - 3x + 7 - 2x + 3

A = 4x - 3x - 2x + 3 + 7 - 8

A = -x + 2

B = (6x² - 5x + 7) - (4x² - 5x - 5)

B = 6x² - 5x + 7 - 4x² + 5x + 5

B = 6x² - 4x² - 5x + 5x + 7 + 5

B = 2x² + 12

C = -(3x² - 5x + 2) + (2x² - 2x + 8) - (3 - 2x + 2x²)

C = -(3x² - 5x + 2) + 2x² - 2x + 8 - 3 + 2x - 2x²

Les x² en gras s'annulent

C = -(3x² - 5x + 2) - 2x + 8 - 3 + 2x

C = -(3x² - 5x + 2) + 8 - 3

C = -3x² + 5x - 2 + 8 - 3

C = -3x² + 5x + 3

Bonne journée :)